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Mapo tofu recipe

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Here's my recipe for Korean-style mapo tofu. It's inspired by Maangchi , Korean Bapsang's , and Just One Cookbook 's recipes. You can use soft, medium, or firm tofu. I bloom the garlic, ginger, and gochujang in oil at the beginning to aim for the feeling of using chili oil. Since these ingredients burn easily, I start with them in a cold pan and then increase the heat while stirring to avoid scorching them. Be warned that the gochugaru might make you sneeze as it blooms. Ingredients: Main ingredients - 1 package of tofu, cut into 1-inch cubes (454 g) - 1/2 package (?) of ground pork or ground beef (227 g) - 6 to 8 green onions (cut into 1-inch long pieces) - 1 onion (cut into chunks, 1 cup) - 1 + 1/4 cups stock (chicken, beef, etc.) — I mix 1 tsp of Knorr chicken broth mix into 1.25 cups of water (1 cup will go into the main dish, the remaining 1/4 cup will be mixed with corn starch to form a slurry to thicken the final dish) - 1 Tbsp gochugaru - 1 Tbsp c...
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Analogy: vectors as colours

  Colours can be encoded as a list of values [R, G, B], and we can conceptualize this as a more abstract type of vector.  "Red", "green", and "blue" behave as our basis vectors from which we can construct all other colours by combining them in varying ratios.  We can also have different basis sets such as the CMYK system. {C, M, Y} forms the basis set. I'm sure there's already an analysis on this in computer graphics!
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SCH4U - Energy Changes and Rates of Reactions Sample Test Qs

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hi guyz it is exam season! i dont feel like typing a real post so im just gonna do some sample problems hehehe 1. Sehee used a coffee cup calorimeter to dissolve 11.86 g of NH4NO3 in 100 mL of water. The initial temperature of the water was 20.5 degC. At the end of the reaction, the temperature recorded was 11.6 degC. Calculate the enthalpy change in kJ/mol of NH4NO3. Indicate if the reaction is exothermic or endothermic. (Heat capacity of water = 4.18 J/g degC) (5 marks) Answer: NH 4 NO 3 Water ΔH sol'n = ? kJ/mol m = 11.86 g M = 2M N + 4M H + 3M O M = [2(14) + 4(1) + 3(16)] g/mol M = 80 g/mol n = m/M n = (11.86 g) / (80 g/mol) n = 0.1483 mol m = 100 g T 1 = 20.5 degC T 2 = 11.6 degC ΔT = (20.5 - 11.6) degC ΔT = 8.9 degC nΔH sol'n = mcΔT n ΔH sol'n = mcΔT / n nΔH sol'n = (100 g)(4.18 J/g degC)(8.9 degC) / 0.1483 nΔH sol'n = 25086 J/mol (extra digits carried) nΔH sol'n = 25.1 kJ/mol the t...
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